URL Decoding the parameters would be necessary if I’m not mistaken. As always, keep it up! You can get an array of items representing the query params using: array = location.search.match(/\w+(.=)?\w*/gi), you can get something like and you can map to an object very easily You may write comments in Markdown thanks to Jetpack Markdown. Next, the .split(/[/?#]/) splits the resulting string based on regex. *$ first group $1 will have it, Your email address will not be published. It has to work for any URL stored in a variable in string format. Note: You can still use an existing URL object for the base, which stringifies itself to the object's href property. While using W3Schools, you agree to have read and accepted our, A String, representing the entire URL of the document, including the protocol (like http://). Great work, this is a really nice bit of coding! QueryString : function(item){ It’s worked where I’ve used it. Otherwise, I like it. var domain = url.replace('http://','').replace('https://','').replace('www. Example: I need ‘jim’ to be inserted as a value of a hidden input field. location.href property. Just a thought. This will return the protocol of the URL in the address bar. or "Tricks". Save my name, email, and website in this browser for the next time I comment. Other examples are also available for your reference. This will return the pathname (value after the domain name) of the URL in the address bar. EX: That works for the most common URLs, such as. The first example will get the current URL in a web browser. This will split out the query part of the url. This works, but I’m far from a regex master, so if any has a better way of doing this, let me know in the comments. var hn = window.location.hostname.split(‘.’).reverse(); Less lines of code, better results: Even better, don’t do the work once for each query string parameter. This will return the anchor portion of the URL including hash sign (#). Thank you. Copyright © 2007 - 2020 Stephen Cronin, All rights reserved. console.log(“Host:”, host); This won’t work for http://domain.com:8080/dsadsa/dsadsa, Or you could avoid the the replace() with….. © 2005-2020 Mozilla and individual contributors. JavaScript creations. Examples might be simplified to improve reading and learning. …works on “//ajax.googleapis.com” aswell and wont care what the protocol was, Oops, make that…. *May or may not contain any actual "CSS" return false; Description: i want rewrite the url by removing the folder path from it. CSS-Tricks* is created, written by, and maintained by Chris Most of the solutions I found suffered from one or more of the following problems: The vast majority of solutions out there work by parsing window.location.hostname or window.location.href. I still want to return “id” value = “predefined value”. }. var svalue = location.search.match(new RegExp(“[\?\&]” + item + “=([^\&]*)(\&? http://rossscrivener.co.uk/blog/javascript-get-domain-exclude-subdomain, http://scratch99.com/web-development/javascript/, JavaScript To Convert Bytes To MB, KB, Etc, How To Create A Silo Structure In WordPress, Creating A JavaScript Array Dynamically Via PHP, WordPress Caching Plugins For Shared Hosting: W3 Total Cache vs WP Super Cache vs Hyper Cache. Thanks…, i need YOUR help for check the last 3 char in the URL. HTTP GET promotes URI addressability so, ... For example, a malicious Web page publisher outside a firewall might put a URI in an HTML page so that, when someone inside the firewall unwittingly follows the link, that person activates a function on another system within the firewall. Calling getQueryVariable(“id”) – would return “1”. The values you can specify are GET, PUT, POST, and DELETE. How about combain this function with if/else? You have to url encode them. I have the same problem as you mentioned in this post and I am wondering if you came up with a solution yet? leverage Jetpack for extra functionality and Local alert(domain); Calling getQueryVariable("image") – would return “awesome.jpg”. getQueryVariable = (variable) -> I have almost no experience with JS. Requests = { example: products/cloths/jeans.aspx has to be rewritten as jeans.aspx. http://www.mywebsite.com/appointment-map.aspx?search=33612, http://mycodingtricks.com/snippets/javascript/get-url-and-url-parts-in-javascript/, http://www.example.com/index.php?id=1&image=awesome.jpg, https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams. My solution, taking all of the problems above into account, is as follows: In the example above, the domain variable will contain the value “scratch99.com”. I, Rahul Kumar am the founder and chief editor of TecAdmin.net. I wanted to use this in CoffeeScript if you want to copy and paste this worked for me But it doesn’t. getQueryVariable("too"); – would return “hisok”. EX: The following examples will all result in scratch99.com being returned: jQuery(document).ready(function($){ Note: This property is similar to the location.href property. This doesn’t cater for user data entry problems, such as the user leaving the : out of a URL, eg: How To Get The Domain From A URL Using JavaScript. which will return scratch99.com, but it won’t work with the following URLs: which would return the full URL in both cases. url.replace(/https?:\/\/([^\/]*)\/. Other examples are also available for your reference. Get the full URL of the current HTML document: The URL property returns the full URL of the current HTML document. i got this one in one scripte i created it What script i can use to declare that condition? Get the latest and greatest from MDN delivered straight to your inbox. Get URL Parameters With JavaScript. Sign in to enjoy the benefits of an MDN account. }); return(false); false can be break a loop and return just first var in your url.. i think that line should be remove.. regards, nb : pardon me if i wrong :) If url is a relative URL, base is required, and will be used as the base URL. query = window.location.search.substring(1), Added another if statement to check for space characters ‘%20’ in the parameters. For example: I’m processing the URL so I can store the domain and use it in a URL, in the following way: http://domain.com/sources/theparseddomain.com/, http://domain.com/sources/http://theparseddomain.com/. However, the solutions I found weren’t robust enough for my needs, so I ended up writing my own. If you just want to strip the “www.”, then you can use the following code in place of line 2 above (note the extra replace): If you need to remove any subdomain, not just www, then you’ll have to do some extra parsing of the result. That suits my needs. You can use the Location object property of the Window object to get these details. var vars = query.split("&"); Required fields are marked *. If we strip it, it will always be the first element. If you want to report an error, or if you want to make a suggestion, do not hesitate to send us an e-mail: W3Schools is optimized for learning and training. var url = $('input#extract_domain').val(); For example, the previous section, called "Relative URIs ", has the value "relative-uris" in its attribute id. They have courses on all the most important front-end technologies, from React to CSS, from Vue to D3, and beyond with Node.js and Full Stack. Let’s say you have the following URL:Here’s a function to give you all the URL parameters as a neat object:You’ll see how this works soon, but first, here are some usage examples:And a demo for you to play around with. That's a good thing! This should be working on older browser too. This technique only returns “false” when setup exactly like described. This would be fine if I was working out the domain of the page I’m currently on, but I want to work it out for a URL that I’m not actually visiting at the moment. if wrong last 3 char it should move to any alert msg page. i tried many scripts but they don’t work for me The first item of the resulting array will be the hostname. http://www.example.com/index.php?id=1&image=awesome.jpg Condition The defines a field for entering a URL. must check last 3 char that is start from dot(.). This will return only the port detail of the URL in the address bar. domain = “http://scratch99.com/web-development/javascript/”.split(/\/\/|\//)[1] hi my friends sorry if i speak english but i can’t explain in french so I dont know if the server has Isapi_rewrite installed. Check this solution here: http://stackoverflow.com/a/901144. If you want to report an error, or if you want to make a suggestion, do not hesitate to send us an e-mail: , W3Schools is optimized for learning and training. Unless the server is being used as a gateway, a partial URL shall be given with the assuptions of the protocol (HTTP:) and server (the server) being obvious. The input value is automatically validated before the form can be submitted. Strings of data octets within a URI are represented as characters. Finally, the [0] gets the first element of the array resulting from the split method. Hey Chris, If the given base URL or the resulting URL are not valid URLs, the JavaScript TypeError exception is thrown. Here is the list of options available to get URL and other details using JavaScript. The string will be split into parts, based not just on the forward slash, but also on the ? If we don’t do this, then depending on whether the http:// is present or not, the domain name may be either the 1st or 3rd element of the split result array. var pair = vars[i].split("="); I've used WordPress since day one all the way up to v17, In our case, we are interested in receiving information, so the first argument we specify is going to be GET. I am a Red Hat Certified Engineer (RHCE) and working as an IT professional since 2009.. Calling getQueryVariable(“image”) – would return “awesome.jpg”. Can anybody let my know exactly where I’m going wrong here? Advertise | Contact | Privacy Policy. i should clarify. Using JavaScript you can easily get the value after the hashtag (#) from the URL, there are no need to use jQuery. When the primary resource is an HTML document, the fragment is often an id attribute of a specific element, and web browsers will scroll this element into view. http://www.domainname.xxx In this article I’m going to present how to get a URL parameter with JavaScript. U have this url www.domain.com?id=1234&img=test.jpg. After the for loop has searched all of the vars (name-value pairs) and hasn’t found variable then this function returns false. If your value has a “&” in it then you’ve got a malformed value. Also, you can get the hash value from href using simple JavaScript code. My question is how can I test for the false return, and then take an action? var query = url; Tip: Always add the
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